# Factorise algebraic expressions by taking out a common algebraic factor (VCMNA329)

**LO: To factorise algebraic expressions by taking out a common algebraic factor.**

**Know:**

- How to find common factors
- How to find common algebraic factors
- What is an algebraic expression

**Understand:**

- That we can factorise algebraic expressions by taking out common algebraic factors.

**Do:**

- I can factorise algebraic expressions.

*Distributive Law*

### The distributive law means to multiply the **coefficient** (number/letters outside of the brackets) by all of the contents** inside** of the brackets.

### In this case, the coefficient is k and I’m going to multiply it by “a” and “b”, which gives me a new expression of ka + kb.

### Factorising is the **opposite action** of expanding brackets.

### The first step to help you factorise common algebraic factors is to break each individual term into** expanded form**.

### In this scenario, we know that 3xy^2 can be expanded into 3 x (x) x (y) x (y).

### 12x^2y can be expanded into 12 x x x x x y or if I want to go even further I can go 2 x 2 x 3 x (x) x (x) x (y).

### Now if you look at both lists, 3 x (x) x (y) is common between** both lists, so they can not be removed to the outside of the brackets, leaving everything else inside the brackets.**

### 3xy(y + 4x)

*Factorising Algebraic Expression Videos*

*Student Generated Videos*

*Textbook Questions*

**My Maths 10**

**My Maths 10**

**Ex 2D pg. 74 Q. 2, 4**

**Ex 2D pg. 74 Q. 2, 4**